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May 26

Unit 11.2. Exponential and Bernoulli distributions

Chapter 11. Maximum likelihood method

Unit 11.2. Exponential and Bernoulli distributions

Exercise 11.1. Suppose the observations come from an exponential distribution with parameter $latex \mu$. Derive the ML estimator of this parameter.

Solution. Step 1. $latex f(x_i | \mu) = \mu e^{-\mu x_i}$.

Step 2. Assuming independent observations, the joint density is a product of these densities $latex \mu^n e^{-\mu x_1} \ldots e^{-\mu x_n}$.

Step 3. The log-likelihood function is

$latex \lambda = n \log \mu - \mu(x_1 + \ldots + x_n).$

The first order condition is

$latex \frac{\partial \lambda}{\partial \mu} = \frac{n}{\mu} - (x_1 + \ldots + x_n) = 0$

and its solution is $latex \mu = \frac{1}{\bar x}$. To make sure that this is a maximum, we need to check the second order condition. Since $latex \frac{\partial^2 \lambda}{\partial \mu^2} = -\frac{n}{\mu^2}$ is negative, we have really found the maximum.

Conclusion: $latex \hat \mu_{ML} = \frac{1}{\bar x}$ is the ML estimator for $latex \mu$.

Exercise 11.2. Suppose that the parent population is Bernoulli. Derive a ML estimator of the parameter $latex p$.

Solution. Step 1. First check that the information in Table 5.7 can be written in the form $latex f(x) = p^x (1 - p)^{1 - x}, \, x = 0, 1$. This function is a discrete analog of a density. Its value at one observation is $latex f(x_i | p) = p^{x_i} (1 - p)^{1 - x_i}$.

Step 2. If the observations are independent, the joint density is

$latex f(x_1, \ldots, x_n | p) = p^{x_1 + \ldots + x_n} (1 - p)^{n - (x_1 + \ldots + x_n)}.$

Step 3. The log-likelihood function is

$latex \lambda = (x_1 + \ldots + x_n) \log p + [n - (x_1 + \ldots + x_n)] \log(1 - p).$

The first order condition is

$latex \frac{\partial \lambda}{\partial p} = \frac{x_1 + \ldots + x_n}{p} - [n - (x_1 + \ldots + x_n)] \frac{1}{1 - p} = 0.$

This is rearranged to

$latex (x_1 + \ldots + x_n) \left( \frac{1}{p} + \frac{1}{1 - p} \right) = \frac{n}{1 - p}.$

Solving for $latex p$ we get $latex p = \frac{x_1 + \ldots + x_n}{n}$. Since we are talking about an estimator, the result should be written as $latex \hat p_{ML} = \bar x$.


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