Euclidean space geometry: scalar product, norm and distance
Learning this material has spillover effects for Stats because everything in this section has analogs for means, variances and covariances.
Definition 1. The scalar product of two vectors is defined by . The motivation has been provided earlier.
Remark. If matrix notation is of essence and are written as column vectors, we have The first notation is better when we want to emphasize symmetry
Linearity. The scalar product is linear in the first argument when the second argument is fixed: for any vectors and numbers one has
Special cases. 1) Homogeneity: by setting we get 2) Additivity: by setting we get
Exercise 1. Formulate and prove the corresponding properties of the scalar product with respect to the second argument.
Definition 2. The vectors are called orthogonal if
Exercise 2. 1) The zero vector is orthogonal to any other vector. 2) If are orthogonal, then any vectors proportional to them are also orthogonal. 3) The unit vectors in are defined by (the unit is in the th place, all other components are zeros), Check that they are pairwise orthogonal.
Exercise 3. On the plane find the distance between a point and the origin.
Once I introduce the notation on a graph (Figure 1), everybody easily finds the distance to be using the Pythagoras theorem. Equally easily, almost everybody fails to connect this simple fact with the ensuing generalizations.
Definition 3. The norm in is defined by It is interpreted as the distance from point to the origin and also the length of the vector .
Exercise 4. 1) Can the norm be negative? We know that, in general, there are two square roots of a positive number: one is positive and the other is negative. The positive one is called an arithmetic square root. Here we are using the arithmetic square root.
2) Using the norm can you define the distance between points
3) The relationship between the norm and scalar product:
True or wrong?
5) How much is If what can you say about
Norm of a linear combination. For any vectors and numbers one has
Proof. From (2) we have
(using linearity in the first argument)
(using linearity in the second argument)
(applying symmetry of the scalar product and (2))
Pythagoras theorem. If are orthogonal, then
This is immediate from (3).
Norm homogeneity. Review the definition of the absolute value and the equation . The norm is homogeneous of degree 1: